First slide
Equation of line in Straight lines
Question

Let the algebraic sum of the perpendicular distances from the points A(2, 0), B(0, 2), C(1, 1) to a variable line be zero. Then, all such lines

Moderate
Solution

Let the variable line be ax + by + c = 0                           (1)
Given, 2a+c+(2b+c)+(a+b+c)a2+b2+c2=0

⇒ 3a + 3b + 3c = 0 or a + b + c = 0.
So, the equation of the line becomes
ax + by – a – b = 0
or, a (x – 1) + b (y – 1) = 0.
⇒ the line passes through the point of intersection of lines
x – 1 = 0 and y – 1 = 0, i.e., the fixed point (1, 1).
So, all such lines are concurrent. Also, (1, 1) is the centroid
of the ΔABC.
 

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