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Q.

Let a1,a2,a3,…a101 are in G.P with a51=25, and ∑i=1101 ai=125.  Then the value of ∑i=1101 1ai is

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a

5

b

15

c

125

d

1125

answer is B.

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Detailed Solution

∑i=1101 ai=a1−r1011−r=125Now ∑i=1101 1ai=1a1+1a2+…+1a101                   =1a1−r1011−r1r100                   =125ar502=125625=1/5
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