Let 3,4are the intercepts of a line then intercepts of a line which is perpendicular to the line and passing through the point 1,3  is

Equation of the line which makes intercepts a,b in axes is xa+yb=1, its slope is −ba Hence the slope of the line which makes intercepts 3,4 on axes is −43 Since required line is perpendicular to the above line, its slope is 34 Equation of the line passing through (1,3) and having slope 34 is y−3=34(x−1)Simplify 4y−12=3x−33x−4y=−9x−3+y94=1 Therefore, the intercepts are −3,94