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Q.

Let a1,a2,a3,…a49,a50 are in A.P. If a1=4, and a50=144 then the value of 1a1+a2+1a2+a3+..+1a49+a50=

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a

1413

b

4914

c

5013

d

4817

answer is B.

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Detailed Solution

1a1+a2+1a2+a3+..+1a49+a50=a2-a1+a3-a2+..+a50-a49d=a50−a1d=144−414049=4914

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