First slide
Theory of expressions
Question

 Let α,β are roots of x2bx=b(b>0) and |α|,|β| are  roots of x2+px+q=0. The minimum value of p28qis equal to

Moderate
Solution

α and β are roots of x2bx=b

 α+β=b,αβ=b|α| and |β| are roots of x2+px+q=0 |α|+|β|=p,|α||β|=q p28q=|α|2+|β|26|α||β| =(α+β)22αβ6|α||β| =b2+2b+6(b)=b24b=(b2)24

 So, minimum value of p28q is 4 . 

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