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 Let A and B are any two events such that P(A)=12 and P(B)=13 then the value of PAcBcc+PAcBcc has the value =

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a
23
b
34
c
45
d
56

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detailed solution

Correct option is D

P(A)=12;P(B)=13PAc∩Bcc=P(A∪B)PAc∪Bcc=P(A∩B)On adding, we get ∴  L.H.S. =P(A)+P(B)=56


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