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Let A=2b1bb2+1b1b2 where b>0.Then the minimum value of detAb is 

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a
−23
b
23
c
−3
d
3

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detailed solution

Correct option is B

det(A)=2b1bb2+1b1b2            =22b2+2-b2-b2b-b+1b2-b2-1            =b2+3 ∴det(A)b=b+3b≥23   ∵AM≥GM⇒b+3b2≥b3b⇒b+3b≥23


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