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Let A=2b1bb2+1b1b2 where b>0.Then the minimum value of detAb is

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a

−23

b

23

c

−3

d

3

answer is B.

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Detailed Solution

det(A)=2b1bb2+1b1b2 =22b2+2-b2-b2b-b+1b2-b2-1 =b2+3 ∴det(A)b=b+3b≥23 ∵AM≥GM⇒b+3b2≥b3b⇒b+3b≥23

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Let A=2b1bb2+1b1b2 where b>0.Then the minimum value of detAb is