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Q.

Let A(a→) and B(b→) be points on two skew lines r→=a→+λp→ and  r→=b→+uq→ and the shortest distance between the skew lines is l, where p→ and q→ are unit vectors forming adjacent sides of a parallelogram enclosing an area of ! units. If an angle between l8 and the line of shortest distance is 60o, then AB =

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a

12

b

2

c

1

d

λ∈R−{0}

answer is B.

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Detailed Solution

1=(b→−a→)⋅(p→×q→)|p→×q→| or  |b→−a→|cos⁡60∘=1⇒AB=2
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