Let A≡(−2,2)  and B≡(2, −2)  be two points and AB subtends an angle of 450  at any point P in the plane in such a way that area of ΔAPB  is 8 square unit, then number of possible position (s) of P is

∵ AB=4  and  area of ΔAPB=8               ∴ 12×4×h=8 ⇒ h=4, h,  the height of ΔAPB  The figure it is clear that P lies on circle of radius 22  unit with AB as its chordso there are four possible position of P.