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Let $A, B$ be the feet of the perpendiculars drawn from $C (1, 1)$ to the pair of lines $7 x^{2} - 20 xy + 12 y^{2} = 0$ . If P is the midpoint of $OC$ then $PA + PB =$

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Correct option is A

Given be the foot of the perpendiculars draw from the point C1,1 to the pair of lines 7x2−20xy+12y2=0The points A,B lies on the circle whose diameter end points are O,CHence, OP=PC=radiusTherefore, PA=PB=OC2=22It implies that PA+PB=2

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Let A,Bbe the feet of the perpendiculars drawn from C1,1 to the pair of lines 7x2−20xy+12y2=0. If P is the midpoint of OC then PA+PB=

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Ready to Test Your Skills?

free study material

Let $A, B$ be the feet of the perpendiculars drawn from $C (1, 1)$ to the pair of lines $7 x^{2} - 20 xy + 12 y^{2} = 0$ . If P is the midpoint of $OC$ then $PA + PB =$