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$Let A and B be two events. Suppose P (A) = 0.4, P (B) = p, and P (A \cup B) = 0.7 . The value of p for which A and B$
$are independent is$

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detailed solution

Correct option is C

P(A∪B)=P(A)+P(B)−P(A)×P(B)⇒ 0.7=0.4+p−0.4p∴ 0.6p=0.3 or p=12

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Let A and B be two events. Suppose P(A)=0.4,P(B)=p, and P(A∪B)=0.7. The value of p for which A and B are independent is

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$Let A and B be two events. Suppose P (A) = 0.4, P (B) = p, and P (A \cup B) = 0.7 . The value of p for which A and B$
$are independent is$