Let A,B be two n×n matrices such that A+B=AB, then
AB=BA
AB = In
A=In or B=In
None of these
Step-I: (A-I)(B-I)
=AB−A−B+I
=AB−A+B+I
=AB-AB+I (∵A+B=AB) AB=IBA=I
Step-II: (B-I)(A-I)=I
BA−B−A+I=I
BA-(A+B)=0 (∵A+B=AB)
BA−AB=0