Let A and B be two sets such that n(A)=0.16, n(B)=0.14, n(A∪B)=0.25. Then n(A∩B) is equal to
0.3
0.5
0.05
None of these
n(A∪B)=n(A)+n(B)-n(A∩B)
0.25=0.16+0.14-n(A∩B)
⇒n(A∩B)=0.30-0.25=0.05.