Let A(2,– 3 ) and B(– 2, 1) be vertices of a triangle ABC. If the centroid of this triangle moves on the line 2x + 3y = 1, then the locus of the vertex C is the line
3x + 2y = 5
2x – 3y = 7
2x + 3y = 9
3x – 2y = 3
Let C(h, k) be the vertex, then the centroid is h+2−23,k−3+13 i.e. (h/3, (k – 2)/3) which lies on 2x + 3y = 1
⇒ 2h3+3(k−2)3=1
⇒ 2h+3k=9 and the locus of (h, k) is 2x + 3y = 9