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 Let A(3,2,0),B(5,3,2),C(9,6,3) are three points forming a triangle. If AD , the  bisector of BAC meets BC in D, then coordinates of D are 

a
−198,5716,1716
b
198,−5716,1716
c
198,5716,−1716
d
198,5716,1716

detailed solution

Correct option is D

A = 3,2,0 ,  B=( 5,3,2) , C -9,6,-3AB = 4+1+4 =3  ,  AC =144+16+9 =13AD = angular bisector  of ∠ BAC since  BD : DC = 3 :13   ⇒  D =-27+6516,18+3916'-9+2616,    by section formula                                          = 3816,5716,1716    =198,5716,1716

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