Questions
Let
, then
equals
detailed solution
Correct option is A
Interchanging the rows and columns, we get Δ=0a−ba−cb−a0b−cc−ac−b0Taking –1 common from each of R1, R2, R3 we getΔ=(−1)30b−ac−aa−b0c−ba−cb−c0Δ=−Δ⇒2Δ=0 or Δ=0Alternative Solution∆ is a skew symmetric determinant of odd order, therefore ∆ = 0Talk to our academic expert!
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If [ ] denotes the greatest integer less than or equal to the real number under consideration, and ,, then the value of the determinant is
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