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Let $Δ = |\begin{array}{lll} 1 a a^{2} - b c \\ 1 b b^{2} - c a \\ 1 c c^{2} - a b \end{array}|$ , then $∆$ is equal to

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Correct option is A

Applying R2→R2−R1+R3→R3−R1 we getΔ=(b−a)(c−a)1 a a2−bc0 1 a+b+c0 1 a+b+c=0 ∵R2 and R3 are identical

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Let Δ=1 a a2−bc1 b b2−ca1 c c2−ab , then∆ is equal to

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Let $Δ = |\begin{array}{lll} 1 a a^{2} - b c \\ 1 b b^{2} - c a \\ 1 c c^{2} - a b \end{array}|$ , then $∆$ is equal to