First slide
Theorems of probability
Question

 Let A,B,C be three events. If the probability of occurring exactly one event out of A and B is 1a, out of B

 and C is 12a, out of C and A is 1a and that of occurring three events simultaneously is a2, then the probability  that at least one out of A,B,C will occur is 

Moderate
Solution

P( exactly one event out of A and B occurs )=PABAB

=P(AB)P(AB)=P(A)+P(B)2P(AB)

 P(A)+P(B)2P(AB)=1a----1

 Similarly, P(B)+P(C)2P(BC)=12a----2

P(C)+P(A)2P(CA)=1a----3P(ABC)=a2---4

now ,P(ABC)

=P(A)+P(B)+P(C)P(AB)P(BC)P(CA)+P(ABC)

=12[P(A)+P(B)2P(BC)+P(B)+P(C)2P(BC)+P(C)+P(A)2P(CA)]+P(ABC)

=12[1a+12a+1a]+a2 [ using (1),(2),(3) and (4)] =322a+a2=12+(a1)2>12

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