First slide
Theorems of probability
Question

Let A, B, C be three mutually independent events. Consider  the two statements S1 and S2.
S1: A and BC are independent
S2: A and BC are independent
Then,

Moderate
Solution

P[A(BC)]=P[(AB)(AC)]=P(AB)+P(AC)P(ABC)=P(A)P(B)+P(A)P(C)P(A)P(B)P(C)=P(A)[P(B)+P(C)P(BC)]=P(A)P(BC)

 Therefore, S1 is true. 

P(A(BC))=P(A)P(B)P(C)=P(A)P(BC)

 Therefore, S2 is also true. 

 

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