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Q.

Let a→,b→ and c→  be the three vectors having magnitudes 1,5 and 3, respectively, such that the angle between a→ and b→ is θ and a→×(a→×b→)=c→  Then tan θ is equal to

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a

0

b

c

3/5

d

¾

answer is D.

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Detailed Solution

a→×(a→×b→)=c→⇒|a→||a→×b→|=|c→|(∵a→⊥(a→×b→))1(1×5)sin⁡θ=3⇒sin⁡θ=35⇒tan⁡θ=34
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