Let A(1,0),B(6,2),C32,6 be the vertices of a triangle ABC. If P is a point inside the triangle ABC such that the triangle APC, APB and BPC have equal areas, then the length of the line segment PQ, where Q is the point −76,−13 is
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answer is 5.
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Detailed Solution
Area of triangle APC, BPC, APB are equal∴P is centroid =1+6+323,0+2+63P=176,83,Q=−76,−13⇒PQ=5