Download the app

Questions  

Let a, b, c, d be any four consecutive coefficients in the binomial expansion of  (1 + x)n,then

aa+b+cc+d2bb+c is equal to

a
n
b
1
c
0
d
2n

detailed solution

Correct option is C

Suppose a=nCr,b=nCr+1,C=nCr+2 and d=nCr+3 Nowaa+b= nCr nCr+nCr+1= nCr n+1Cr+1=r+1n+1Similarly, bb+c=(r+1)+1n+1 and cc+d=(r+2)+1n+1Thus, aa+b+cc+d−2bb+c=0

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

The coefficient of x7 in the expression (1+x)10+x(1+x)9+x2(1+x)8++x10 is


phone icon
whats app icon