Let a, b, c, d and e be distinct positive number. If a, b, c and 1c,1d,1eboth are in A.P. and b, c, d are in G.P. then
a,b,c are in G.P.
a,b,c are in A.P
a, c, e are in A.P.
a, c, e are in G.P
2b=a+c,2d=1c+1e,c2=bd
Now, 2cec+e=d=c2b
⇒ec+e=c2b=ca+c⇒ae+ce=c2+ce
⇒c2=ae⇒a,c,e are in G.P.