Let a, b, c, d and p be any non zero distinct real numbers such that a2+b2+c2p2−2ab+bc+cdp+b2+c2+d2=0. Then:
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a
a, b, c, d are in G.P
b
a, c, p are in G.P
c
a, c, p are in A.P
d
a, b, c, d are in A.P
answer is A.
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Detailed Solution
a,b,c,d∈R° are all different Given a2+b2+c2p2-2(ab+bc+cd)p+b2+c2+d2=0⇒(ap-b)2+(bp-c)2+(cp-d)2=0⇒ap-b=0 and bp-c=0 and cp-d=0⇒p=ba=cb=dc⇒a,b,c,d are in G.P