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Geometric progression

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Question

Let a, b and c from a G.P of common ratio r, with 0  <  r  <1. If a, 2b and 3c form an A.P. then r equals ___________

Easy
Solution

b=ar,  c=ar2

 a, 2b,3c are in A .P 

 4b=a+3c

  4ar=a+3ar2

3r2-4r+1=0

r=1,13  (where r 1

 So, r=13


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