First slide
Operations of matrix
Question

Let a, b, c R be such that a+b+c>0 and abc=2. Let A=a    b    cb    c    ac    a    b If A2=I, then value of a3+b3+c3 is

Moderate
Solution

A2=a    b    cb    c    ac    a    ba    b    cb    c    ac    a    b=αβββαβββα
where α=a2+b2+c2,
          β=bc+ca+ab.
As A2=I, we get
a2+b2+c2=α=1
bc+ca+ab=0
Now, (a+b+c)2=α+2β=1
  a+b+c=1
We have 
a3+b3+c33abc=(a+b+c)a2+b2+c2bccaab=1a3+b3+c3=7

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