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Let a, b, c R be such that a+b+c>0 and abc=2. Let A=a    b    cb    c    ac    a    b If A2=I, then value of a3+b3+c3 is

a
7
b
2
c
0
d
-1

detailed solution

Correct option is A

A2=a    b    cb    c    ac    a    ba    b    cb    c    ac    a    b=αβββαβββαwhere α=a2+b2+c2,          β=bc+ca+ab.As A2=I, we geta2+b2+c2=α=1bc+ca+ab=0Now, (a+b+c)2=α+2β=1⇒  a+b+c=1We have a3+b3+c3−3abc=(a+b+c)a2+b2+c2−bc−ca−ab=1⇒a3+b3+c3=7

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