Let a + b + c = s and s+cabcs+abcas+b=532, then the value of s is __________ .
Given that
s+cabcs+abcas+b=532
Applying C1→C1+C2+C3, we get
(a+b+c+s)1ab1s+ab1as+b=532
⇒ 2s0−s00s−s1as+b=532⇒ 2s3=532
∴ s3=216
s = 6