Let a,b∈ℝ and f:ℝ⇒ℝ be defined by f(x)=acosx3-x+b|x|sinx3+x . Then f , is
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a
Differentiable at x=0 if a=0 and b=1
b
Differentiable at x=1 if a=1 and b=0
c
NOT differentiable at x=0 if a=1 and b=0
d
NOT differentiable at x=1 if a=1 and b=1
answer is A.
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Detailed Solution
fx = a cosx -x3+bx sinx3+x if x∈0,1 =a cosx3-x+b x sinx3+x if x∈-1,0f'0+ =-a sinx-x31-3x2+bsinx3+x+bx cosx3+x3x2+1 =-a0+b0+b0=0 f'0-=-a sinx3-x3x2-1+b sinx3+x+bx cosx3+x3x2+1 =-a0+b0+b0=0 hence fx is differentiable at x=0 for all a,b, hence if a=0,b=1 now fx = a cosx3-x +bx sinx3+x if x≥1 fx = a cosx -x3+bx sinx3+x if x∈0,1 f'1+=f'1-= b cos24+bsin2 hence fx is differentiable at x=1 for a,b hence if a=1,b=1