Let A≡(3,−4),B≡(1,2) . Let P≡(2k−1,2k+1) be a variable point such that PA + PB is the minimum. Then kis
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a
79
b
0
c
78
d
9
answer is C.
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Detailed Solution
PA+PB is minimum only when A,B,P are collinear If three points are collinear then the slopes of the lines joining any two points is same PA slope is 2k+52k-4 and AB slope is 6-2 Equate the slopes and then solve for k 2k+52k-4=-3 2k+5=-6k+12 8k=7 k=78