First slide

Introduction to Relations (XI) on Sets

Question

Let $A = \{1, 2, 3, 4, 5\}; B = \{2, 3, 6, 7\} .$ Then the number of elements in $(A \times B) \cap (B \times A)$ is

Easy

A

18
B

6
C

4
D

0

Solution

Here A and B sets having 2 elements in common, so $A \times B and B \times A$ have $2^{2}$ i.e., 4 elements in common.
Hence, $n [(A \times B) \cap (B \times A)] = 4 .$

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