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let A and B two invertible matrices of order  3X3. If det ABAT=8 and det AB-1=8, then det BA1BT is 

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a
1
b
14
c
116
d
16

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detailed solution

Correct option is C

We have |A||B|AT=8  and  |A|1B=8  ∵B-1=1B|A|2|B|=8→ (1)  |A|=8|B|→(2)               ∵AT=A (1) ⇒64|B|3=8     ⇒|B|=12 and |A|=4∴BA-1BT=|B|=1|A||B|T=121412=116


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