Let ω be the complex number cos2π3+isin2π3. Then the number of distinct complex numbers z satisfying z+1ωω2ωz+ω21ω21z+ω=0 is equal to _________.
ω=ei2π/3
z+1ωω2ωz+ω21ω21z+ω=0z1ωω21z+ω2111z+ω=0
(Applying C1→C1+C2+C3 and using 1+ω+ω2=0 )
or zz+ω2(z+ω)−1−ω(z+ω−1)+ω21−z−ω2=0or z3=0or z=0 is only solution.