First slide

Introduction to Determinants

Question

Let $ω \neq 1$ be a cube root of unity and $Δ = |\begin{array}{ccc} 1 - ω - ω^{2} & 2 & 2 \\ 2 ω & ω - ω^{2} - 1 & 2 ω \\ 2 ω^{2} & 2 ω^{2} & ω^{2} - 1 - ω \end{array}|$ then $∆$ equals

Moderate

A

$- ω$
B

$3 ω (1 - ω)$
C

0
D

$1 = ω^{2}$

Solution

Using $R_{1} \to R_{1} + R_{2} + R_{3}$ and $1 + ω + ω^{2} = 0$ we obtain
$Δ = 0$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App