Q.

Let ω≠1 be a cube root of unity and   Δ=1−ω−ω2222ωω−ω2−12ω2ω22ω2ω2−1−ω then ∆ equals

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a

−ω

b

3ω(1−ω)

c

0

d

1=ω2

answer is C.

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Detailed Solution

Using R1→R1+R2+R3 and 1+ω+ω2=0 we obtainΔ=0
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