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Q.

Let  ω≠1,  be a cube  root of unity, and f :I→C be defined by f(n)=1+ωn+ω2n then range of f is

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a

0

b

0,3

c

0,1,3

d

0,1

answer is B.

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Detailed Solution

If  n=3k,k∈I then f(n)=1+1+1=3If n=3k+1,k∈I then  f(n)=1+ω+ω2=0If n = 3k + 2 k ∈ I, then f(n) = 1 + w2 + w = 0Thus, range of f is 0,3.
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