Let α and β be non-zero real numbers such that 2(cosβ−cosα)+cosαcosβ=1. Then which of the following is/are true?
tanα2+3tanβ2=0
3tanα2+tanβ2=0
tanα2−3tanβ2=0
3tanα2−tanβ2=0
cosβ(2+cosα)=1+2cosα
⇒ cosβ1=1+2cosα2+cosα⇒ 1−cosβ1+cosβ=1−cosα3(1+cosα)⇒ tan2α2=3tan2β2⇒ tanα2=±3tanβ2