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Let $a_{1}, a_{2}, \dots, a_{10}$ be in A.P and $h_{1}, h_{2} . . . . . h_{10}$ be in H.P. If $a_{1} = h_{1} = 2$ and
$a_{10} = h_{10} = 3,$ then $a_{4} h_{7}$ is

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Correct option is D

Let d be the common difference of the A.P…., then 3=a10=2+9d ⇒ d=1/9∴ a1=2+3d=7/3Next, let D be the common difference of the A.P.1h1,1h2,…,1h10 Then 13=1h10=12+9D⇒D=−154∴ 1h7=1h1+6D=718⇒h7=187Hence, a4h7=(7/3)(18/7)=6.

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Let a1, a2,…,a10 be in A.P and h1, h2.....h10 be in H.P. If a1=h1=2 anda10=h10=3, then a4h7 is

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Let $a_{1}, a_{2}, \dots, a_{10}$ be in A.P and $h_{1}, h_{2} . . . . . h_{10}$ be in H.P. If $a_{1} = h_{1} = 2$ and
$a_{10} = h_{10} = 3,$ then $a_{4} h_{7}$ is