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 Let α and β be the roots of the equation px2+qx+r=0,p0. If p,q,r are in  A.P., and 1α+1β then the value of |αβ| is: 

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a
619
b
2179
c
349
d
2139

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detailed solution

Correct option is D

Given p,q,r are in A.P 2q=p+r Also 1α+1β=4;α+βαβ=4−q/pr/p=4; q=−4r−8r=p+4; p=−9rpx2+qx+r=0−9rx2−4rx+r=09x2+4x−1=0|α−β|=(α+β)2−4αβ=1681+49=529=2139


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