Let α,β,γ be the roots of the equation (x−a)(x−b)(x−c)=d,d≠0 the roots of the equation (x−α)(x−β)(x−γ)+d=0 are

Since, α,β,γ are the roots of (x−a)(x−b)(x−c)=d  ⇒ (x−a)(x−b)(x−c)−d=(x−α)(x−β)(x−γ) ⇒ (x−α)(x−β)(x−γ)+d=(x−a)(x−b)(x−c)⇒a, b and c are the roots of(x−α)(x−β)(x−γ)+d=0