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Questions  

 Let α,β and γ be the roots of the equation x3x2+3x+1=0 . Then the value of γ    β    α+2β+2γα    γ    β+2α+2γβ    α    γ+2α+2β is equal to 

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a
-10
b
-8
c
7
d
9

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detailed solution

Correct option is B

Δ=γβα+2β+2γαγβ+2α+2γβαγ+2α+2β Applying C3→C3−2C1−2C2, we get Δ=γβααγββαγ=(α+β+γ)α2+β2+γ2−αβ−βγ−γα=(α+β+γ)(α+β+γ)2−3(αβ+βγ+γα)=1×12−3×(3)=−8


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If 

a2b2c2(a+λ)2(b+λ)2(c+λ)2(aλ)2(bλ)2(cλ)2=kλa2b2c2abc111

λ  0 then k is equal to:


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