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Theory of expressions

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By Expert Faculty of Sri Chaitanya
Question

Let  α and β be the roots of equation X2 - 6x - 2 = O. If an=αnβn, for n1,then the value a102a82a9 as is equal to

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Solution

Given,α and β are the roots of the equation
x26x2=0
an=αnβn for n1 a10=α10β10 a8=α8β8a9=α9β9
Now, consider
a102a82a9=α10β102α8β82α9β9
=α8α22β8β222α9β9=α86αβ86β2α9β9=6α96β92α9β9=62=3α and β are the  roots of x26x2=0 or  x2=6x+2 α2=6α+2α22=6α and β2=6β+2β22=6β


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