Let α and β be the roots of the equation x2+x+1=0. The equation whose roots are α19, β7 is
x2-x-1=0
x2-x+1=0
x2+x-1=0
x2+x+1=0
Given x2+x+1=0
∴x=12[-1±i3]=12(-1+i3), 12(-1-i3)=ω, ω2.
But α19=ω19=ω and β7=ω14=ω2.
Hence the equation will be same.