Let α and β be the roots of the quadratic equation px2+qx+r=0, where αβ=99. If p,q and r (taken in that order)
are in arithmetic progression, then (α+β) is equal to
α+β=−qp;αβ=rp Also, 2q=p+r⇒2qp=1+rp⇒−2(α+β)=1+αβ=1+99=100⇒(α+β)=−50