First slide
Introduction to limits
Question

Let α and βbe the roots of ax2+bx+c=0,then Ltxα1cos(ax2+bx+c)(xα)2=

Moderate
Solution

ax2+bx+c=a(xα)(xβ)given limit is Limxα2sin2(a(xα)(xβ)2)2(xα)2=a2(αβ)22  

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