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Let A be a set containing n elements. The number of ways of choosing two subsets Pand  Q of  A such that 

PQ=ϕ is 

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a
2n
b
3n
c
4n - 2n
d
4n - 3n

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detailed solution

Correct option is B

For each x∈A, we have four choices;(i)  x∈P,x∈Q(ii)  x∈P,x∉Q(iii) x∉P,x∈Q(iv) x∉P,x∉QOut of these four choices, last 3 choices imply x∉P∩QThus,  P and  Q can be chosen in 3n ways so thatP∩Q=ϕ


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