Let A be a set of n (≥ 3) distinct elements. The number of triplets (x, y, z) of the A elements in which at least two coordinates is equal to
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a
nP3
b
n3−nP3
c
3n2−2n
d
3n2(n−1)
answer is B.
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Detailed Solution
Total number of triplets without restriction is n×n×n.The number of triplets with all different coordinates is nP3.Therefore, the required number of triplets is n3−n(n−1)(n−2).