Let A be the set of non-negative integers, I is the set of integers, B is the set of non-positive integers, E is the set of even integers and P is the set of prime numbers then.

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I−A=B

A∩B=ϕ

E∩P=ϕ

AΔB=I−{0}

answer is D.

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Detailed Solution

AΔB=A−B∪B−A=1,2,3.....∪.....−3,−2,−1=.....−3,−2,−1,1,2,3....=I−0

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