Questions
Let be such that are in A.P , are in G.P.; and are in H.P. Then are in
detailed solution
Correct option is A
We have, a1,a2,a3are in A.P.⇒2a2=a1+a3----i a2,a3,a4are in G.P.⇒a32=a2a4-----ii a3,a4,a5are in H.P.⇒a4=2a3a5a3+a5-----iiiPutting a2=a1+a32 and a4=2a3a5a3+a5 in (ii), we geta32=a1+a32×2a3a5a3+a5⇒ a32=a1a5⇒a1,a3,a5are in G.P.Similar Questions
If the roots of the equation,
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