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Let a1,a2,a3,a4 and a5 be such that a1,a2 and a3 are in A.P ,a2,a3 and a4 are in G.P.; and a3,a4 and a5 are in H.P. Then a1,a3 and a5 are in

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G.P
b
A.P
c
H.P
d
None of these

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detailed solution

Correct option is A

We have, a1,a2,a3are in A.P.⇒2a2=a1+a3----i a2,a3,a4are in G.P.⇒a32=a2a4-----ii a3,a4,a5are in H.P.⇒a4=2a3a5a3+a5-----iiiPutting a2=a1+a32 and a4=2a3a5a3+a5 in (ii), we geta32=a1+a32×2a3a5a3+a5⇒ a32=a1a5⇒a1,a3,a5are in G.P.


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