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Q.

Let a1, a2, a3....be terms of an A.P. If a1+a2+…+apa1+a2+…+aq=p2q2,p≠q then a6a21

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a

1141

b

4111

c

72

d

27

answer is A.

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Detailed Solution

p2[2a+(p−1)d]q2[2a+(q−1)d]=p2q2⇒a+p−12da+q−12d=pqNow, put p = 11 and q = 41.
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