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Let α, β, γ be three real numbers and A=1cos(βα)cos(γα)cos(αβ)1cos(γβ)cos(αγ)cos(βγ)1 then

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a
Ais singular
b
Ais non-singular
c
Ais orthogonal
d
none of these

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detailed solution

Correct option is A

|A|=1cos⁡(β−α)cos⁡(γ−α)cos⁡(α−β)1cos⁡(γ−β)cos⁡(α−γ)cos⁡(β−γ)1=cos⁡αsin⁡α0cos⁡βsin⁡β0cos⁡γcos⁡γ0cos⁡αsin⁡α0cos⁡βsin⁡β0cos⁡γsin⁡γ0=0⇒  A is singular.


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