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Q.

Let in a Binomial distribution, consisting of 5 independent trials, probabilities of exactly 1 and 2 successes be 0.4096 and 0. 2048 respectively. Then the probability of getting exactly 3 successes is equal to:

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a

40243

b

128625

c

80243

d

32625

answer is D.

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Detailed Solution

n=5,p(x=1)=5pq4=0.4096,     p(x=2)=10p2q3=0.2048 Dividing we get q=4p ∴p=15,q=45   p(x=3)=10p3q2=32625
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